A girl starts from rest and reaches a walking speed of 1.4 m/s in 3.0 s. She walks at this speed for 6.0 s. Girl then slows down and comes to a stop during a 10.0 -s period. What was her acceleration during each of the 3 time periods? Her acdeleration entire trip!?

Ok so i solved it all but only im not sure about the entire trip acceleration i got o m/s squared but she changed speed..

Her acceleration entire trip (Vf-Vi)/time

which of course is zero.

Yo this was a long time ago. Even before bts debuted...just ignore me yall, I'm tryna find an answer too TT. Anyway stream dynamite

To calculate the acceleration during each time period, we can use the formula:

Acceleration = Change in velocity / Time

1. Initial Acceleration (from rest to 1.4 m/s in 3.0 s):

Acceleration = (1.4 m/s - 0 m/s) / 3.0 s
Acceleration = 1.4 m/s / 3.0 s
Acceleration = 0.47 m/s²

2. Constant Acceleration (walking at 1.4 m/s for 6.0 s):

Acceleration = (1.4 m/s - 1.4 m/s) / 6.0 s
Acceleration = 0 m/s / 6.0 s
Acceleration = 0 m/s²

3. Final Deceleration (from 1.4 m/s to 0 m/s in 10.0 s):

Acceleration = (0 m/s - 1.4 m/s) / 10.0 s
Acceleration = -1.4 m/s / 10.0 s
Acceleration = -0.14 m/s²

4. Total Acceleration (entire trip):

To find the total acceleration, we calculate the average acceleration over the entire trip. Since there were three different accelerations in the trip, we can first find the total change in velocity and the total change in time.

Total change in velocity = 1.4 m/s - 0 m/s = 1.4 m/s
Total change in time = 3.0 s + 6.0 s + 10.0 s = 19.0 s

Now, we can calculate the total acceleration:

Acceleration = Total change in velocity / Total change in time
Acceleration = 1.4 m/s / 19.0 s
Acceleration ≈ 0.074 m/s²

So, the total acceleration for the entire trip is approximately 0.074 m/s².

To find the acceleration during each of the three time periods, we need to use the equation of motion:

Acceleration = (Final Velocity - Initial Velocity) / Time

1. To find the acceleration from rest to a walking speed of 1.4 m/s in 3.0 s:
Initial Velocity = 0 m/s (rest)
Final Velocity = 1.4 m/s
Time = 3.0 s

Acceleration1 = (1.4 m/s - 0 m/s) / 3.0 s
Acceleration1 = 1.4 m/s / 3.0 s
Acceleration1 ≈ 0.47 m/s²

2. To find the acceleration during the period when the girl walks steadily at 1.4 m/s for 6.0 s:
Initial Velocity = 1.4 m/s
Final Velocity = 1.4 m/s (constant speed)
Time = 6.0 s

Acceleration2 = (1.4 m/s - 1.4 m/s) / 6.0 s
Acceleration2 = 0 m/s / 6.0 s
Acceleration2 = 0 m/s²

3. To find the acceleration when the girl slows down and comes to a stop in 10.0 s:
Initial Velocity = 1.4 m/s (constant speed)
Final Velocity = 0 m/s (stop)
Time = 10.0 s

Acceleration3 = (0 m/s - 1.4 m/s) / 10.0 s
Acceleration3 = -1.4 m/s / 10.0 s
Acceleration3 ≈ -0.14 m/s²

Now, to find the acceleration for the entire trip, we need to consider that acceleration is the rate of change of velocity. So, we can calculate the overall acceleration using the average acceleration formula:

Average Acceleration = Total Change in Velocity / Total Time

Total Change in Velocity = Final Velocity - Initial Velocity
Total Time = 3.0 s + 6.0 s + 10.0 s

Total Change in Velocity = 0 m/s - 1.4 m/s
Total Time = 3.0 s + 6.0 s + 10.0 s

Total Change in Velocity = -1.4 m/s
Total Time = 19.0 s

Average Acceleration = -1.4 m/s / 19.0 s
Average Acceleration ≈ -0.074 m/s²

So, the acceleration for the entire trip is approximately -0.074 m/s².