Each side of a square is lengthened by 2 inches. The area of this new, larger square is 81 square inches. Find the length of a side of the original square.

√81 = 9

9 - 2 = 7

Factor any difference of two squares, or state that the polynomial is prime. Assume any variable exponents represent whole numbers. 2 - 36

X

Well, well, well, we have a square that decided to go on a growth spurt! Let's call the side length of the original square 'x'. So, the new square has a side length of 'x + 2', right? Now, according to your problem, the area of the new square is 81 square inches. So, what's the equation we can cook up here? Well, Area = Side length squared. So, the area of the new square is (x + 2) squared, which gives us 81. Now, let's simplify things. Expand that (x + 2) squared term and set it equal to 81. Solve that equation, and voila! You'll find the length of a side of the original square. Good luck, my square-loving friend!

Let's assume that the length of each side of the original square is 'x' inches.

If each side of the square is lengthened by 2 inches, the new length of each side would be 'x + 2' inches.

The area of a square is given by the formula: Area = side^2.

Thus, the area of the larger square is (x + 2)^2 = 81 square inches.

Expanding this equation gives us x^2 + 4x + 4 = 81.

Subtracting 81 from both sides, we get x^2 + 4x - 77 = 0.

Now, we can solve this quadratic equation to find the value of 'x'.

To solve this problem, we can use algebra. Let's denote the length of a side of the original square as "x".

According to the given information, each side of the original square is lengthened by 2 inches. Therefore, the length of a side of the larger square, which is formed by lengthening each side of the original square, will be "x + 2".

The area of a square is calculated by squaring the length of one of its sides. So, the area of the larger square is (x + 2) * (x + 2), which is equal to 81 square inches.

To find the length of the side of the original square, we need to solve the equation (x + 2) * (x + 2) = 81 for "x".

Expanding the equation, we get x^2 + 4x + 4 = 81.

Rearranging, we have x^2 + 4x - 77 = 0.

Now we can solve this quadratic equation. There are multiple methods to solve quadratic equations, such as factoring, completing the square, or using the quadratic formula.

Using the quadratic formula, x = (-b ± √(b^2 - 4ac)) / 2a, where a, b, and c are the coefficients in the quadratic equation ax^2 + bx + c = 0.

For our equation x^2 + 4x - 77 = 0, a = 1, b = 4, and c = -77.

Plugging these values into the quadratic formula, we get x = (-4 ± √(4^2 - 4*1*(-77))) / (2*1).

Simplifying further, x = (-4 ± √(16 + 308)) / 2.

Calculating, x = (-4 ± √324) / 2.

Since we are looking for the length of a side, which cannot be negative, we can disregard the negative solution.

Therefore, x = (-4 + √324) / 2.

Simplifying, x = (-4 + 18) / 2.

Finally, x = 14 / 2.

Thus, the length of a side of the original square is 7 inches.