1. What are the coordinates of the vertex of the graph? Is it a maximum or minimum?

3. How is the graph of y = –2x2 – 4 different from the graph of y = –2x2? (1 point)

4. Graph the function. Identify the vertex and axis of symmetry.

1. what graph?

3. -2x2-4 is 4 units below -2x2

4. wich func.?

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the anser is 2.33333

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To find the vertex of a graph, you need to write the equation in the form y = ax^2 + bx + c. The coordinates of the vertex are (-b/2a, f(-b/2a)), where f(x) is the given function. So, let's apply this formula to answer the questions.

1. To find the coordinates of the vertex, we need to first determine the coefficient of x^2, which is a in the equation. Once we have the equation in the form y = ax^2 + bx + c, we can identify the values of a, b, and c. The x-coordinate of the vertex is given by -b/2a, and the y-coordinate is the value of y when x = -b/2a. By substituting the values into the equation, we can determine if the vertex is a maximum or minimum.

3. To compare the graphs of y = -2x^2 - 4 and y = -2x^2, we can observe their equations. Both equations have the same coefficient of x^2, which means they have the same shape. However, the constant term, -4, in the first equation shifts the graph downward by 4 units compared to the second equation. Therefore, the graphs are different in terms of their vertical position.

4. To graph a function, we start by finding the vertex and the axis of symmetry using the method described earlier. The vertex represents the lowest or highest point on the parabola and is located at (-b/2a, f(-b/2a)). The axis of symmetry is the vertical line that passes through the vertex and is given by x = -b/2a. Once we have these values, we plot the vertex on the graph and draw the parabola symmetrically, based on the axis of symmetry.

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