What is the specific heat in J/g Celsius for a metal sample with a mass 95.6 g which absorbs 841 J of energy when it's temperature increases from 30.0 degrees Celsius to 98.0 degrees Celsius?
841J=95.6g×c×68c =0.129/gc
q = mc*delta T
Well, well, well, seems like we have a metal sample with a fancy temperature change, don't we? Well, fear not my curious comrade, for Clown Bot is here to assist you!
To calculate the specific heat (c) for this metal sample, we can use the formula:
Q = mcΔT
Now, let's break it down:
Q represents the heat energy absorbed or released, m is the mass of the sample, c is the specific heat, and ΔT represents the change in temperature.
In this case, we know that Q = 841 J, m = 95.6 g, ΔT = (98.0 °C - 30.0 °C) = 68.0 °C.
Now, let's plug in the values and solve for c:
841 J = (95.6 g) (c) (68.0 °C)
Divide both sides of the equation by (95.6 g) (68.0 °C):
841 J / (95.6 g) (68.0 °C) = c
And after crunching the numbers, we find that the specific heat (c) for this metal sample is approximately 0.136 J/g°C.
Now, wasn't that temperature transformation a real hot topic? I hope my clownish explanation brought a smile to your face!
To find the specific heat capacity (c) of the metal sample, we can use the equation Q = mcΔT, where Q is the heat absorbed, m is the mass of the sample, c is the specific heat capacity, and ΔT is the change in temperature.
Given:
Mass (m) = 95.6 g
Heat absorbed (Q) = 841 J
Initial temperature (T₁) = 30.0 °C
Final temperature (T₂) = 98.0 °C
First, we need to find the change in temperature (ΔT):
ΔT = T₂ - T₁
= 98.0 °C - 30.0 °C
= 68.0 °C
Now we can substitute the values into the formula Q = mcΔT and solve for c:
841 J = (95.6 g) * c * 68.0 °C
To find the specific heat capacity in J/g °C, we need to divide both sides of the equation by the mass of the sample (m):
841 J = (95.6 g) * c * 68.0 °C
c = 841 J / (95.6 g * 68.0 °C)
c ≈ 0.168 J/g °C
Therefore, the specific heat capacity of the metal sample is approximately 0.168 J/g °C.
To find the specific heat capacity (C) in J/g°C, we can use the formula:
C = q / (m × ΔT)
where:
- C is the specific heat capacity in J/g°C
- q is the energy absorbed in Joules (J)
- m is the mass of the sample in grams (g)
- ΔT is the change in temperature in degrees Celsius (°C)
In this case, the given values are:
- q = 841 J
- m = 95.6 g
- ΔT = 98.0°C - 30.0°C = 68.0°C
Now, substitute these values into the formula:
C = 841 J / (95.6 g × 68.0°C)
First, multiply the mass (m) by the change in temperature (ΔT):
C = 841 J / (6504.8 g°C)
Divide the energy (q) by the result:
C ≈ 0.13 J/g°C
Therefore, the specific heat capacity of the metal sample is approximately 0.13 J/g°C.