When 20.0 g C2H6 and 60.0 g O2 react to form CO2 and H2O, how many grams of water are formed?

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To determine the number of grams of water formed when 20.0 g of C2H6 and 60.0 g of O2 react to form CO2 and H2O, we need to follow a few steps.

Step 1: Write the balanced chemical equation for the reaction.
The balanced chemical equation for the reaction between C2H6 (ethane) and O2 (oxygen) to form CO2 (carbon dioxide) and H2O (water) is:

C2H6 + O2 -> CO2 + H2O

Step 2: Calculate the molar mass of the substances involved.
The molar mass of C2H6 is determined by adding up the atomic masses of carbon (C) and hydrogen (H) in the molecule:
Carbon (C) atomic mass: 12.01 g/mol
Hydrogen (H) atomic mass: 1.01 g/mol

So, molar mass of C2H6 = (2 * 12.01 g/mol) + (6 * 1.01 g/mol) = 30.07 g/mol

Similarly, the molar mass of O2 is calculated by adding up the atomic masses of oxygen (O):
Oxygen (O) atomic mass: 16.00 g/mol

So, molar mass of O2 = (2 * 16.00 g/mol) = 32.00 g/mol

The molar mass of CO2 is calculated by adding up the atomic masses of carbon (C) and two oxygen (O) atoms:
Carbon (C) atomic mass: 12.01 g/mol
Oxygen (O) atomic mass: 16.00 g/mol

So, molar mass of CO2 = 12.01 g/mol + (2 * 16.00 g/mol) = 44.01 g/mol

The molar mass of H2O is calculated by adding up the atomic masses of two hydrogen (H) atoms and one oxygen (O) atom:
Hydrogen (H) atomic mass: 1.01 g/mol
Oxygen (O) atomic mass: 16.00 g/mol

So, molar mass of H2O = (2 * 1.01 g/mol) + 16.00 g/mol = 18.02 g/mol

Step 3: Determine the moles of the given substances.
To determine the moles of C2H6 and O2, divide their given masses by their respective molar masses:

Moles of C2H6 = 20.0 g / 30.07 g/mol = 0.665 mol
Moles of O2 = 60.0 g / 32.00 g/mol = 1.875 mol

Step 4: Use the balanced chemical equation to determine the moles of water formed.
From the balanced equation, we can see that the mole ratio between C2H6 and H2O is 1:3. This means that for every 1 mole of C2H6, 3 moles of H2O are formed.

Since we have 0.665 moles of C2H6, we can calculate the moles of water formed as follows:

Moles of H2O = 0.665 mol C2H6 * 3 mol H2O / 1 mol C2H6 = 1.995 mol H2O

Step 5: Calculate the mass of water formed.
Finally, to calculate the mass of water formed, multiply the moles of H2O by its molar mass:

Mass of H2O = 1.995 mol H2O * 18.02 g/mol = 35.89 g

Therefore, when 20.0 g of C2H6 and 60.0 g of O2 react, 35.89 g of water are formed.