if 150 grams of water is heated from 20 degrees C to 30 degrees C, the number of joules of heat energy aborbed is?

q = mass H2O x specific heat H2O x (Tfinal-Tinitial)

45000

To calculate the amount of heat energy absorbed, you can use the formula:

Q = m * c * ΔT

Where:
Q is the heat energy (in joules)
m is the mass of the substance (in grams)
c is the specific heat capacity of the substance (water is approximately 4.18 J/g°C)
ΔT is the change in temperature (in degrees Celsius)

Given:
m = 150 grams
c = 4.18 J/g°C
ΔT = 30°C - 20°C = 10°C

Now let's substitute the values into the formula and calculate:

Q = 150 g * 4.18 J/g°C * 10°C
Q = 6270 J

Therefore, the number of joules of heat energy absorbed by 150 grams of water when heated from 20 degrees Celsius to 30 degrees Celsius is 6270 joules.

To calculate the amount of heat energy absorbed by the water, you need to use the formula:

Q = mcΔT

Where:
Q is the heat energy absorbed or released (in joules)
m is the mass of the substance (in grams)
c is the specific heat capacity of the substance (in joules per gram per degree Celsius)
ΔT is the change in temperature (in degrees Celsius)

Given:
m = 150 grams (mass of water)
c = 4.184 J/g°C (specific heat capacity of water)
ΔT = 30°C - 20°C = 10°C (change in temperature)

Now, plug in the values into the formula:

Q = 150 grams * 4.184 J/g°C * 10°C

Calculating the product:

Q = 6276 joules

Therefore, the number of joules of heat energy absorbed by 150 grams of water heated from 20°C to 30°C is 6276 joules.