The bases on a baseball diamond are 90 feet apart. How far is it from home plate to second base?
Please explain
Use the Pythagorean Theorem.
a^2 + b^2 = c^2
90^2 + 90^2 = c^2
8,100 + 8,100 = c^2
16,200 = c^2
127.28 = c
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David leaves the house to go to school. He walks 200m west and 125m north. How far
away is he from his starting point? (the diagonal)
explain please
thanks
Thanks very much
Yess
The length of each side of a baseball diamond is 90 feet. What is the distance from 2nd to home plate? Please explain.
On a baseball diamond, the bases are 90 feet apart. How many yards does a batter run in reaching second base?
To find the distance from home plate to second base, we need to calculate the hypotenuse of a right triangle. The two sides of the right triangle are the distance from home plate to first base (90 feet) and the distance from first base to second base (90 feet).
We can use the Pythagorean theorem, which states that in a right triangle, the square of the hypotenuse (c) is equal to the sum of the squares of the other two sides (a and b).
Using the Pythagorean theorem, we can calculate the distance from home plate to second base as follows:
c^2 = a^2 + b^2
c^2 = (90 ft)^2 + (90 ft)^2
c^2 = 8100 ft^2 + 8100 ft^2
c^2 = 16200 ft^2
c = √16200 ft
c ≈ 127.28 ft
Therefore, it is approximately 127.28 feet from home plate to second base.