Just need some help...
Directions:
Multiply or raise to the power as indicated... Then simplify the result. Assume all variables represent positive numbers.
1. 5(square root of 6) times two-thirds(square root of 15)= 3 one-third (square root of 90)= (This is where i am stuck...) 3 one-third (square root of 9) (Square root of 5) (Square root of 2) which would = 9.9 (square root of 5) (Square root of 2)
2. -4 square root of a times 3 square root of a= You would get -12, but what do you do to the a's... Thanks!!!
1. What do you want to get for this question?
2.-12a
Miltiply whole numbers and roots separately. So 3 one third of 90 means 10/3 root 90 and 5 root of 6 * 2/3 root 15 becomes 10/3 root 90. Therefore 10/3 root 90=10/3 root 90. Which will be 1=1 after dividing both sides by 10/3 root 90.
To simplify the expressions, we need to simplify each radical term and then multiply them together.
For the first problem:
1. Multiply the coefficients: 5 * (2/3) = (10/3).
2. Multiply the radical terms: √6 * √15 = √90.
To simplify the radical term, we can break it down into factors. Since √90 = √(9 * 10), we can simplify it to √9 * √10 = 3 * √10.
3. Combining the coefficients and the radical terms, we have:
(10/3) * (3 * √10) = 10 * √10.
Therefore, the simplified result is 10√10.
For the second problem:
1. Multiply the coefficients: -4 * 3 = -12.
2. Multiply the radical terms: √a * √a = √(a * a) = √(a^2) = a.
Since both terms have the same radical (√a), when multiplied together, they simplify to a.
3. Combining the coefficient and the radical term, we have:
-12 * a.
Therefore, the simplified result is -12a.