A textbook store sold a combined total of 315 physics and chemistry textbooks in a week. The number of physics textbooks sold was two times the number of chemistry textbooks sold. How many textbooks of each type were sold?

Let x = the number of chemistry textbooks.

x + 2x = 315

3x = 315

x = 105

p + c = 315

p =2c

Replace p with the 2c in the first equation.

2c + c = 315

solve for "c"

then you can find p.

To find the number of physics and chemistry textbooks sold, let's set up a system of equations.

Let's say the number of chemistry textbooks sold is C.
According to the problem, the number of physics textbooks sold is two times the number of chemistry textbooks sold. Therefore, the number of physics textbooks sold is 2C.

The total number of textbooks sold is 315, so we can write the equation:
C + 2C = 315

Combining like terms, we can simplify the equation to:
3C = 315

Now, we can solve for C by dividing both sides of the equation by 3:
C = 315 / 3
C = 105

So, the number of chemistry textbooks sold (C) is 105.

To find the number of physics textbooks sold, we can substitute the value of C back into the equation:
2C = 2 * 105
2C = 210

So, the number of physics textbooks sold is 210.

Therefore, 105 chemistry textbooks and 210 physics textbooks were sold.

Y=105

X=210