What is the molarity of a solution prepared by dissolving 8 grams of BaCl2 in enough water to make a 450.0 mL solution?

2 answers

  1. Molarity is moles/liter

    8 grams/molecular weight of BaCl2

    You will have moles in /450 = ?? moles/1000

  2. Molarity =moles of solute /volume of soln in let.
    Moles of BaCl2=given mass /molecular mass
    =8/80=1/10 =0.1moles.
    Now,
    M=0.1/0.45=10/45=2/9 =0.222molar.

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