if the mole fractionof sulfuric acid (H2SO4) in an aqueous solitioin is 0.325, what is the percent by mass of H2SO4?

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if the mole fractionof sulfuric acid (H2SO4) in an aqueous solitioin is 0.325, what is the percent by mass of H2SO4?

Answer 1 · 2013-03-03 19:52:55

XH2SO4 = 0.325
XH2O = 1-0.325 = 0.675

XH2SO4 = mols H2SO4/total mols.
1 mol H2SO4 = 98 grams.
0.325 mol H2SO4 = 0.3 x 98 = 31.85g H2SO4 in 0.675 x 18 = 12.15 g H2O

Total mass = 12.15 + 31.85 = 44.0 g
% H2SO4 = (g H2SO4/total g)*100 =
(31.85/44)*100 = ?

Answer 2 · 2020-06-09 21:14:11

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if the mole fractionof sulfuric acid (H2SO4) in an aqueous solitioin is 0.325, what is the percent by mass of H2SO4?

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