if the mole fractionof sulfuric acid (H2SO4) in an aqueous solitioin is 0.325, what is the percent by mass of H2SO4?

3 answers

  1. XH2SO4 = 0.325
    XH2O = 1-0.325 = 0.675

    XH2SO4 = mols H2SO4/total mols.
    1 mol H2SO4 = 98 grams.
    0.325 mol H2SO4 = 0.3 x 98 = 31.85g H2SO4 in 0.675 x 18 = 12.15 g H2O

    Total mass = 12.15 + 31.85 = 44.0 g
    % H2SO4 = (g H2SO4/total g)*100 =
    (31.85/44)*100 = ?

  2. Actually, I have the same question in the book but i didn't know how to solve it, so I was searching and I found this website. Thank you very much and BYE

  3. 31%

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