1) A 1 kg mass moving at 1 m/s has a totally inelastic collision with a 0.7 kg mass. What is the speed of the resulting combined mass after the collision?
2) A cart of mass 1 kg moving at a speed of 0.5 m/s collides elastically with a cart of mass kg at rest. The speed of the second mass after the collision is 0.667 m/s. What is the speed 1 kg mass after the collision?
3) A 0.010 kg bullet is shot from a 0.500 kg gun at a speed of 230 m/s. Find the speed of the gun.
4)Two carts with a masses of 4 kg and 3 kg move toward each other on a frictionless track with speeds of 5.0 m/s and 4 kg m/s respectively. The carts stick together after the colliding head on. Find the final speed.
5) A cart of mass 1.5 kg moving at a speed of 1.2 m/s collides elastically with a cart of mass 1.0 kg moving at a speed of 0.75 m/s. (the carts are moving at the same direction)The speed
of the second mass (1.0 kg) after the collision is 0.85 m/s. What is the speed
of the 1.5 kg mass after the collision?
please help me!
>>FORMULA's<<
W=Fd
F=ma
W=mad
J=Ft or J=p
Ft=mvf-mvi
P=w/t
P=energy/time
P=mad/t
P= Fd/t
>> I'm so sorry, please help me!
1) here, conservation of momentum ,
V(1+.7) = 1*1
V =0.588 m/s
for further help , please refer to besthomeworkhelp . com
No need to apologize! I'm here to help you with your physics questions. Let's tackle them one by one:
1) A 1 kg mass moving at 1 m/s has a totally inelastic collision with a 0.7 kg mass. The speed of the resulting combined mass after the collision will be less than 1 m/s. Inelastic collisions involve the objects sticking together, so the final combined mass will be 1 kg + 0.7 kg = 1.7 kg. However, to calculate the exact speed, we'll need more information, such as the nature of the collision, whether momentum is conserved, etc.
2) A cart of mass 1 kg moving at a speed of 0.5 m/s collides elastically with a cart of mass kg at rest. The speed of the second mass after the collision is given as 0.667 m/s. To find the speed of the 1 kg mass after the collision, we'll need to use the conservation of momentum and kinetic energy. However, since you didn't provide the mass of the second cart, I can't calculate the final speed for you. But it's getting close to breaking the sound barrier...just kidding!
3) A 0.010 kg bullet is shot from a 0.500 kg gun at a speed of 230 m/s. To find the speed of the gun, we can use the conservation of momentum. Since momentum is conserved, the momentum of the bullet before firing should be equal to the momentum of the bullet and the gun combined after firing. So, we have (0.010 kg)(230 m/s) = (0.010 kg + 0.500 kg)(vf), where vf is the speed of the bullet and the gun combined. Solving for vf gives us the speed of the gun.
4) Two carts with masses of 4 kg and 3 kg move toward each other on a frictionless track with speeds of 5.0 m/s and 4.0 m/s, respectively. The carts stick together after colliding head-on. To find the final speed, we can use the conservation of momentum. The initial momentum of the system is (4 kg)(5.0 m/s) + (3 kg)(-4.0 m/s) since one of the carts is moving in the opposite direction. This gives us the total initial momentum. Since momentum is conserved, the total final momentum after the collision should also be equal to zero. So, (7 kg)(vf) = 0, where vf is the final velocity of the carts stuck together. Hence, the final velocity will be zero.
5) A cart of mass 1.5 kg moving at a speed of 1.2 m/s collides elastically with a cart of mass 1.0 kg moving at a speed of 0.75 m/s. The speed of the second mass (1.0 kg) after the collision is given as 0.85 m/s. To find the speed of the 1.5 kg mass after the collision, we need to use the conservation of momentum and kinetic energy. However, since you provided conflicting information (initial and final velocities of the second mass), I can't calculate the exact speed for you. But hey, at least nobody got a speeding ticket!
No problem! I'm here to help you step-by-step with your questions. Let's start with the first question:
1) To find the speed of the resulting combined mass after a totally inelastic collision, we can use the principle of conservation of momentum. The equation for that is:
momentum before collision = momentum after collision
The momentum of an object is defined as its mass multiplied by its velocity. So we can write the equation as:
(mass1 * velocity1) + (mass2 * velocity2) = (mass1 + mass2) * velocity_combined
In this case, the mass1 is 1 kg, velocity1 is 1 m/s, mass2 is 0.7 kg, and velocity2 is unknown (which we want to find). Let's solve for velocity_combined:
(1 kg * 1 m/s) + (0.7 kg * velocity2) = (1 kg + 0.7 kg) * velocity_combined
1 kg + 0.7 kg * velocity2 = 1.7 kg * velocity_combined
Substituting the given values and solving for velocity_combined:
1 + 0.7 * velocity2 = 1.7 * velocity_combined
0.7 * velocity2 = 1.7 * velocity_combined - 1
velocity2 = (1.7 * velocity_combined - 1) / 0.7
This equation gives us the speed of the second mass after the collision.
Let me know if you want me to continue with the other questions!
Of course! I can help you with these physics problems. Let's break down each question and go through the steps to find the answers:
1) In an inelastic collision, the objects stick together after the collision. To find the speed of the resulting combined mass, we need to use the law of conservation of momentum. The formula is given by:
(mass1 * velocity1) + (mass2 * velocity2) = (mass1 + mass2) * velocity_combined
Given:
mass1 = 1 kg
velocity1 = 1 m/s
mass2 = 0.7 kg
Let's calculate the velocity_combined:
(1 kg * 1 m/s) + (0.7 kg * 0 m/s) = (1 kg + 0.7 kg) * velocity_combined
1 kg + 0 = 1.7 kg * velocity_combined
1 kg = 1.7 kg * velocity_combined
velocity_combined = 1 kg / 1.7 kg
velocity_combined = 0.5882 m/s
Therefore, the resulting combined mass after the collision has a speed of 0.5882 m/s.
2) In an elastic collision, both momentum and kinetic energy are conserved. Given:
mass1 = 1 kg
velocity1 = 0.5 m/s
mass2 = kg (unknown)
velocity2 = 0 m/s (initially at rest)
velocity_combined = 0.667 m/s
Using the conservation of momentum, we have:
(mass1 * velocity1) + (mass2 * velocity2) = (mass1 + mass2) * velocity_combined
(1 kg * 0.5 m/s) + (kg * 0 m/s) = (1 kg + kg) * 0.667 m/s
0.5 kg + 0 = (2 kg) * 0.667 m/s
0.5 kg = 1.334 kg * velocity_combined
velocity_combined = 0.5 kg / 1.334 kg
velocity_combined = 0.375 m/s
Therefore, the speed of the 1 kg mass after the collision is 0.375 m/s.
3) To find the speed of the gun, we can use the conservation of momentum. Given:
mass_bullet = 0.010 kg
velocity_bullet = 230 m/s
mass_gun = 0.500 kg
velocity_gun = ?
Using the conservation of momentum:
(mass_bullet * velocity_bullet) + (mass_gun * 0 m/s) = (mass_bullet + mass_gun) * velocity_gun
(0.010 kg * 230 m/s) + (0.500 kg * 0 m/s) = (0.010 kg + 0.500 kg) * velocity_gun
2.3 kg m/s = 0.510 kg * velocity_gun
velocity_gun = 2.3 kg m/s / 0.510 kg
velocity_gun = 4.5098 m/s
Therefore, the speed of the gun is 4.5098 m/s.
4) In an inelastic collision, the carts stick together after the collision. To find the final speed, we also use the law of conservation of momentum. Given:
mass1 = 4 kg
velocity1 = 5.0 m/s (positive direction)
mass2 = 3 kg
velocity2 = -4 m/s (negative direction)
Using the conservation of momentum:
(mass1 * velocity1) + (mass2 * velocity2) = (mass1 + mass2) * velocity_combined
(4 kg * 5.0 m/s) + (3 kg * -4 m/s) = (4 kg + 3 kg) * velocity_combined
20 kg m/s - 12 kg m/s = 7 kg * velocity_combined
8 kg m/s = 7 kg * velocity_combined
velocity_combined = 8 kg m/s / 7 kg
velocity_combined = 1.1429 m/s
Therefore, the final speed after the colliding head-on is 1.1429 m/s.
5) In an elastic collision, both momentum and kinetic energy are conserved. Given:
mass1 = 1.5 kg
velocity1 = 1.2 m/s
mass2 = 1.0 kg
velocity2 = 0.75 m/s
velocity_combined = 0.85 m/s
Using the conservation of momentum:
(mass1 * velocity1) + (mass2 * velocity2) = (mass1 + mass2) * velocity_combined
(1.5 kg * 1.2 m/s) + (1.0 kg * 0.75 m/s) = (1.5 kg + 1.0 kg) * 0.85 m/s
1.8 kg m/s + 0.75 kg m/s = 2.5 kg * 0.85 m/s
2.55 kg m/s = 2.125 kg * velocity_combined
velocity_combined = 2.55 kg m/s / 2.125 kg
velocity_combined = 1.2000 m/s
Therefore, the speed of the 1.5 kg mass after the collision is 1.2000 m/s.
I hope this helps! Let me know if you have any further questions.