a bullet of mass 0.01kg is fired into a sandbag of mass 0.49kg handing from atree.the sandbag with the bullet embedded into it swing away at 10m/s find: a.the momentum after collision b.the momentum before the collision c.the velocity of the bullet
A)Pf=(m1+m2)v
= (0.01+0.49)10
=5 Kgm/s
B)Po=Pf so it's the same as the first one.
C)v=0.05
I hate it u didn't even give me good answers just stupid ones and no explanation
a. (.01+.49)10
b. same as a.
c. .01V=momentum in b.
0.01v=5kgm/s is 500m/s
A.5
B.5
C.,500
you're good but can you make it brief abt the sol
anyway thank you for your help
A.5
B.5
C.500
by what angle velocity will be 0.05m/s?
A.5
B.5
C.500