a bullet of mass 0.01kg is fired into a sandbag of mass 0.49kg handing from atree.the sandbag with the bullet embedded into it swing away at 10m/s find: a.the momentum after collision b.the momentum before the collision c.the velocity of the bullet

A)Pf=(m1+m2)v

= (0.01+0.49)10
=5 Kgm/s
B)Po=Pf so it's the same as the first one.
C)v=0.05

I hate it u didn't even give me good answers just stupid ones and no explanation

a. (.01+.49)10

b. same as a.

c. .01V=momentum in b.

0.01v=5kgm/s is 500m/s

A.5

B.5
C.,500

you're good but can you make it brief abt the sol


anyway thank you for your help

A.5

B.5
C.500

by what angle velocity will be 0.05m/s?

A.5

B.5
C.500

Mohammed