Two horizontal forces, F1> and F2> , are acting on a box, but only F1>is shown in the drawing. F2> can point either to the right or to the left. The box moves only along the x axis. There is no friction between the box and the surface. Suppose that F1> = +8.0 N and the mass of the box is 4.7 kg. Find the magnitude and direction of F2> when the acceleration of the box is (a) +6.7 m/s2, (b) 6.7 m/s2, and (c) 0 m /s2.
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1 answer

You first have to find the acceleration of what is given. F1 has force of +8.0N, and box has mass of 4.7kg.
F = ma, so 8.0/4.7 is 1.7m/s2.
Now to view the other question, you'd use the same equation only this time, you need to use the newly acquired acceleration from above.
F2 = (4.7)(6.71.7) = 23.5N
F2 = (4.7)(6.71.7) = 39.48N
F2 = (4.7)(01.7) = 7.99N 👍
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answered by Megan
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