Determine the final velocity of a proton that has an initial velocity of 2.35 x 10^5 m/s, and then is accelerated uniformly in an electric field at the rate of -1.10 x x 10^12 m/s squared for 1.50 x 10^-7 s.

V = Vo + a*t.

V=2.35*10^5 -1.1*10^12*1.5*10^-7=
70000m/s.

21

Well, well, well, we've got a proton on the move! Let's get this party started and calculate that final velocity.

To determine the final velocity, we can use the equation of motion:

v = u + at

Where:
v is the final velocity,
u is the initial velocity,
a is the acceleration, and
t is the time taken.

Now, plug in the given values:
u = 2.35 x 10^5 m/s (The initial velocity)
a = -1.10 x 10^12 m/s^2 (The acceleration)
t = 1.50 x 10^-7 s (The time taken)

Calculating the final velocity, we get:

v = (2.35 x 10^5 m/s) + (-1.10 x 10^12 m/s^2)(1.50 x 10^-7 s)

And if my math circus skills are on point, the final velocity of our speedy proton will be... drumroll, please... approximately -3.605 m/s.

So, it looks like our proton is heading out with a velocity of -3.605 m/s. Just hope it doesn't get too charged up along the way!

To determine the final velocity of the proton, we can use the equations of motion for uniformly accelerated linear motion.

The equation we will utilize is:

v = u + at

where:
v is the final velocity,
u is the initial velocity,
a is the acceleration, and
t is the time.

Let's plug in the given values:

Initial velocity, u = 2.35 x 10^5 m/s
Acceleration, a = -1.10 x 10^12 m/s^2 (negative sign indicates a deceleration)
Time, t = 1.50 x 10^-7 s

Substituting the values into the equation:

v = 2.35 x 10^5 m/s + (-1.10 x 10^12 m/s^2) x (1.50 x 10^-7 s)

Now, let's calculate this:

v = 2.35 x 10^5 m/s - 1.65 x 10^5 m/s

v = 0.7 x 10^5 m/s

Therefore, the final velocity of the proton is 7 x 10^4 m/s.