The voltage across a membrane forming a cell wall is 80.0 mV and the membrane is 8.80 nm thick. What is the electric field strength? (The value is surprisingly large, but correct. Membranes are discussed in Section 19.7* of the textbook.) You may assume a uniform E-field.

To find the electric field strength, we can use the formula:

Electric field strength (E) = Voltage (V) / Distance (d)

Given:
Voltage (V) = 80.0 mV = 80.0 x 10^(-3) V (convert mV to V)
Distance (d) = 8.80 nm = 8.80 x 10^(-9) m (convert nm to m)

Now we can substitute the values into the formula to calculate the electric field strength:

E = V / d
E = (80.0 x 10^(-3) V) / (8.80 x 10^(-9) m)

To simplify this calculation, we can divide the numerator and the denominator by 10^(-9):

E = (80.0 x 10^(-3) V) / (8.80 x 10^(-9) m)
E = (80.0 / 8.80) V / m
E ≈ 9.09 x 10^(6) V/m

Therefore, the electric field strength is approximately 9.09 x 10^(6) V/m.

To find the electric field strength across the membrane, we can use the formula:

Electric field strength (E) = Voltage (V) / Distance (d)

Given:
Voltage (V) = 80.0 mV = 80.0 × 10^-3 V
Distance (d) = 8.80 nm = 8.80 × 10^-9 m

Plugging in these values into the formula, we have:

E = (80.0 × 10^-3 V) / (8.80 × 10^-9 m)

Now, let's simplify and calculate the electric field strength:

E = 9.09 × 10^6 V/m

Therefore, the electric field strength across the membrane is 9.09 × 10^6 V/m.

E = (deltaV)/(thickness)

= 80*10^-3/8.8*10^-9 (V/m)
= 9.1*10^6 V/m