Median family income in country x between 1990 and 1999 can be modeled by f(x)=1144.7(x-1990)+35,834 where x is the year. Determine the median income was $42,303.

I did it this way don't know if it's right
f(x)=1144.7(x-1990)+35,834
42,303-35,834 = 1144.7 - (x-1990) + 35,834
6469. 1144 7 - (x-1990). 35,834

.177=x-1990
The median income was $1144.7 every year

Thanks for all your help:-)

F(x) = 1144.7(x-1990) + 35,834 = $42303.

1144.7x for y - 2277953 + 35834 = 42303
1144.7x - 2242119 = 42303
1144.7x = 2284422
X = 1995.65 or 1996.

The Median income was $42,303 for year
1996.

To determine the year when the median income was $42,303, you need to solve for x in the equation:

f(x) = 1144.7(x-1990) + 35,834

Set f(x) equal to the given median income:

42,303 = 1144.7(x-1990) + 35,834

To solve for x, let's start by subtracting 35,834 from both sides:

42,303 - 35,834 = 1144.7(x-1990)

6,469 = 1144.7(x-1990)

Next, divide both sides by 1144.7:

6,469 / 1144.7 = x - 1990

Simplifying, we get:

5.653 = x - 1990

Finally, to isolate x, add 1990 to both sides:

5.653 + 1990 = x

1995.653 = x

Therefore, the median income of $42,303 was reached in the year 1995.

To determine the year when the median income was $42,303, you need to solve the equation:

42,303 = 1144.7(x - 1990) + 35,834

Let's solve it step by step:

1. First, subtract 35,834 from both sides of the equation:

42,303 - 35,834 = 1144.7(x - 1990)

This simplifies to:

6,469 = 1144.7(x - 1990)

2. Divide both sides of the equation by 1144.7:

6,469 / 1144.7 = x - 1990

This simplifies to:

5.65 = x - 1990

3. Add 1990 to both sides of the equation:

5.65 + 1990 = x

This simplifies to:

1995.65 = x

Therefore, the median family income was $42,303 in the year 1995.