If 25 grams of copper(II) sulfate pentahydrate were heated until all water was removed, how much residue would remain?- Could someone help me understand this question? I don't understand it at all. Thanks

CuSO4.5H2O ==> CuSO4 + 5H2O

The question is asking how much CuSO4 is left if all of the H2O is driven off.
The easy way to do this is calculate % water in CuSO4.5H2O.

Since there is 5H2O is about 36% of CUSO4 + 5H2O , would there be about 16 g of residue left over? Thanks

ABOUT, yes. It's about 64% CuSO4 so

0.64 x 25 = about 16.

Certainly! The question is asking about the amount of residue that would remain after heating 25 grams of copper(II) sulfate pentahydrate to remove all the water.

To understand the question, let's break it down:

1. Copper(II) sulfate pentahydrate: This is a compound consisting of copper(II) ions (Cu2+), sulfate ions (SO4^2-), and five water molecules (penta- refers to five). The molecule formula is CuSO4·5H2O.

2. Heating until all water is removed: When heated, the water molecules in copper(II) sulfate pentahydrate evaporate, leaving behind the anhydrous form of the compound, which is copper(II) sulfate (CuSO4).

3. Amount of residue: This refers to the remaining substance or solid that remains after the water has been removed.

So, the question is asking how much copper(II) sulfate will remain after all the water has evaporated from the initial 25 grams of copper(II) sulfate pentahydrate.

To find the answer, we need to calculate the amount of copper(II) sulfate in the initial 25 grams of copper(II) sulfate pentahydrate by subtracting the mass of water.

Since each molecule of copper(II) sulfate pentahydrate contains 5 water molecules, we need to determine the mass of water in 25 grams of copper(II) sulfate pentahydrate. To do this, we multiply the molar mass of water (18 g/mol) by 5 and subtract that value from 25 grams.

Once we know the mass of water, we subtract it from the total mass of copper(II) sulfate pentahydrate to find the mass of the residue, which is the anhydrous copper(II) sulfate.

I hope this explanation helps you understand the question better! Let me know if you need further assistance.