You decide to establish a new temperature scale on which the melting point of ammonia (-77.75 C ) is 0 A, and the boiling point of ammonia (-33.35 C ) is 200 A.

What would be the boiling point of water in A ?

What would be the temperature of absolute zero in A ?

I think I answered this one for you already in a later post!!!!!!!!

To determine the boiling point of water in the new temperature scale, we need to find the linear relationship between the two scales using the given melting and boiling points of ammonia.

The difference in temperatures between the melting and boiling points of ammonia on the new scale is 200 A - 0 A = 200 A.

The difference in temperatures between the melting and boiling points of ammonia in Celsius is -33.35°C - (-77.75°C) = 44.4°C.

To find the conversion factor between the two scales, we divide the difference in temperatures in the new scale by the difference in temperatures in Celsius:

Conversion factor = (200 A) / (44.4°C)

Now we can find the boiling point of water in A using the conversion factor.

The boiling point of water in Celsius is 100°C.

Boiling point of water in A = Conversion factor * 100°C

Now we can calculate it:

Boiling point of water in A = (200 A / 44.4°C) * 100°C

Boiling point of water in A ≈ 450 A

Therefore, the boiling point of water in A would be approximately 450 A.

To find the temperature of absolute zero in the new scale, we need to determine the equivalent temperature in A.

Absolute zero in Celsius is -273.15°C.

Temperature of absolute zero in A = Conversion factor * (-273.15°C)

Now we can calculate it:

Temperature of absolute zero in A = (200 A / 44.4°C) * (-273.15°C)

Temperature of absolute zero in A ≈ -1233 A

Therefore, the temperature of absolute zero in A would be approximately -1233 A.

To determine the boiling point of water in the new temperature scale, we need to establish a linear relationship between the temperatures in Celsius and the new temperature scale (A).

First, we'll find the slope of this linear relationship. The change in Celsius temperature for ammonia is 200°C (from its boiling point to its melting point), and the change in the new temperature scale (A) is 200 A (from 0 A to 200 A).

Slope (m) = Change in A / Change in °C = 200 A / 200°C = 1.

Therefore, the slope of the linear relationship between the new temperature scale and Celsius is 1.

Next, we can find the y-intercept of this linear relationship. Since the melting point of ammonia is 0 A, and its corresponding temperature in Celsius is -77.75°C, we can set up the equation as follows:

0 A = 1 * (-77.75)°C + b (where b is the y-intercept)

Simplifying the equation, we have:

0 A = -77.75°C + b
b = 77.75°C

Now that we have the slope (m = 1) and the y-intercept (b = 77.75°C), we can use the equation for a straight line (y = mx + b) to convert Celsius temperature to the new scale (A).

For the boiling point of water in Celsius, it is 100°C. Using the linear equation, we substitute the Celsius temperature (x) to find the temperature in the new scale (y):

y = 1 * 100°C + 77.75°C
y = 177.75°C

Therefore, the boiling point of water in the new temperature scale (A) would be 177.75 A.

Now let's find the temperature of absolute zero in the new temperature scale. Absolute zero is the lowest possible temperature and is equal to -273.15°C. Using the linear equation:

y = 1 * (-273.15°C) + 77.75°C
y = -195.4°C

Hence, the temperature of absolute zero in the new temperature scale (A) would be -195.4 A.