A rifle bullet is fired directly upward from the ground. Its height above the ground at any instant of time t is given by the formula, s = 63t - 9.8t2. Assuming there is no air resistance how high will the bullet rise?
height in meters =
My Answer
S'= 63-19t
s"=0-19.6
Height in meters = 19.6
Can you please confirm this is correct
thanks!
300 divide by 6 =50
Bella, did you post this answer in the wrong question????
To find the height the bullet will reach, we need to find the maximum point on the parabolic trajectory described by the equation s = 63t - 9.8t^2.
The height of the bullet is represented by s, which is given as a function of time t. To find the maximum point, we need to find the time at which the height is maximized.
To do this, we can take the derivative of s with respect to t, and set it equal to zero. This will give us the time at which the bullet reaches its maximum height:
s' = 63 - 19.6t
Setting s' = 0:
0 = 63 - 19.6t
Solving for t:
t = 63 / 19.6 ≈ 3.22 seconds
So, the time it takes for the bullet to reach its maximum height is approximately 3.22 seconds.
To find the maximum height, we substitute this value of t back into the original equation for s:
s = 63t - 9.8t^2
s = 63 * 3.22 - 9.8 * (3.22)^2
s ≈ 204.86 meters
Therefore, the bullet will rise to a height of approximately 204.86 meters above the ground.