calcium carbonate decomposes if heated to form calcium oxide and carbon dioxide. if 24.5 grams of calcium carbonate decompose how many moles of calcium carbonate reacted?

24.5g * 1mole/100.09g = 24.48 moles

To determine the number of moles of calcium carbonate that reacted, you need to use the molar mass of calcium carbonate and the given mass of calcium carbonate.

The molar mass of calcium carbonate (CaCO3) is calculated by adding up the atomic masses of its constituent elements:
- Atomic mass of calcium (Ca) = 40.08 g/mol
- Atomic mass of carbon (C) = 12.01 g/mol
- Atomic mass of oxygen (O) = 16.00 g/mol (there are three oxygen atoms in calcium carbonate)

Now, let's calculate the molar mass of calcium carbonate:
Molar mass of CaCO3 = (1 × atomic mass of Ca) + (1 × atomic mass of C) + (3 × atomic mass of O)
Molar mass of CaCO3 = (1 × 40.08 g/mol) + (1 × 12.01 g/mol) + (3 × 16.00 g/mol)
Molar mass of CaCO3 = 40.08 g/mol + 12.01 g/mol + 48.00 g/mol
Molar mass of CaCO3 = 100.09 g/mol

Now, you can calculate the number of moles of calcium carbonate consumed using the given mass of calcium carbonate:

Number of moles = Mass / Molar mass
Number of moles = 24.5 g / 100.09 g/mol

Calculating this will give you the answer:

Number of moles = 0.2453 mol (rounded to four decimal places)

Therefore, 0.2453 moles of calcium carbonate reacted.