If the equilibrium concentrations are [PCl5] = 1.0M, [Cl2] = 0.10M, what is the equilibrium constant value?
PCl5(g) <---> PCl3(g) + Cl2(g)
Would you mind showing the calculations Please. I've been working on this problem over an hour now. Not certain if I am working it correctly Thank you so much.
In the future you should realize that you could show your work and we could look at it in a jiffy and know what is right or wrong. As it is, you work it out, post a NEW question, we work it, type it, post it. THEN YOU COMPARE IT WITH YOUR NOTES. All of this takes too much time FROM US. Many times we don't have the time to work it and do all that typing so we don't answer the question. However, if YOU take the time to type it, we can respond quickly. Having said all of that I have the time tonight so here is how you do it.
.........PCl5 ==> PCl3 + Cl2
E........1.0M......x.....0.10M
If Cl2 is 0.10M, then PCl3 MUST be 0.10M also. Then
Kc = (PCl5)/(Cl2)(PCl3)
Kc = (1.0)/(0.1)(0.1)
Check my work to make sure there are no typos.
Kc = 100
Well, buckle up because I'm about to make equilibrium calculations as fun as a clown car ride!
To find the equilibrium constant (Kc), we need to use the concentrations of the reactants and products at equilibrium. In this case, we have [PCl5] = 1.0M and [Cl2] = 0.10M.
The equilibrium constant expression for the given reaction is:
Kc = [PCl3] * [Cl2] / [PCl5]
Since we are given the concentrations of PCl5 and Cl2, we need to find the concentration of PCl3. Let's call it x.
At equilibrium, the change in the concentration of PCl5 will be -x (since it's being consumed), and the change in the concentration of Cl2 will be -x. The change in the concentration of PCl3 will be +x (since it's being produced).
So, at equilibrium, the concentrations will be:
[PCl5] = 1.0 - x
[Cl2] = 0.10 - x
[PCl3] = x
Now, we can substitute these values into the equilibrium constant expression:
Kc = [PCl3] * [Cl2] / [PCl5]
= (x)*(0.10-x) / (1.0-x)
And that's it! You now have the equilibrium constant expression for the given reaction. You can plug in the values of x as calculated from the equilibrium concentrations to find the equilibrium constant value.
Although, I must admit, equilibrium constants are not always the funniest clowns at the chemistry circus. But hey, they're essential for understanding the balance of reactions!
To find the equilibrium constant value (Kc), we need to use the equation:
Kc = ([PCl3] * [Cl2]) / [PCl5]
Given:
[PCl5] = 1.0 M
[Cl2] = 0.10 M
We need to find the concentration of PCl3. The balanced equation tells us that the ratio of moles of PCl5 to moles of PCl3 is 1:1. Therefore, if we assume that x M of PCl5 reacts, x M of PCl3 will be formed.
At equilibrium, the initial concentration of PCl5 (1.0 M) will decrease by x M, and the initial concentration of Cl2 (0.10 M) will also decrease by x M. Therefore, the equilibrium concentrations are:
[PCl5] (at equilibrium) = 1.0 - x M
[Cl2] (at equilibrium) = 0.10 - x M
[PCl3] (at equilibrium) = x M
Substituting these values into the equation for Kc, we get:
Kc = ([PCl3] * [Cl2]) / [PCl5]
= (x * (0.10 - x)) / (1.0 - x)
This is the expression for the equilibrium constant value.
To calculate the equilibrium constant (K) for the given reaction, you need to use the equilibrium concentrations of the substances involved in the reaction.
The balanced equation shows that the stoichiometric coefficients of the reacting species are in a 1:1:1 ratio. So, at equilibrium, the concentrations of PCl3 and Cl2 will be the same.
Given:
[PCl5] = 1.0 M
[Cl2] = 0.10 M
The expression for the equilibrium constant (K) is given by the formula:
K = ([PCl3] * [Cl2]) / [PCl5]
To solve for K, you need to determine the concentration of PCl3 at equilibrium.
Using the stoichiometry of the reaction, you know that for every 1 mole of PCl5 that reacts, 1 mole of PCl3 is produced. Therefore, the concentration of PCl3 at equilibrium will also be 1.0 M.
Now, substitute the given values into the formula:
K = (1.0 M * 0.10 M) / 1.0 M
K = 0.10
Therefore, the equilibrium constant (K) for the given reaction is 0.10.