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An electron with a horizontal speed of 4.0 * 10^6 m/s and no vertical component of velocity passes through two horizontal parallel plates. The magnitude of the electric field between the plates is 150 n/c the plates are 6.0 long

A) calculate the vertical component of the electron's final velocity. (Ans 4.0 * 10^5)
B) calculate the final velocity of the electron. (Ana4.0 * 10^6)
Please with full solution

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1 answer

  1. v(x)=4•10⁶ m/s,
    E=150 N/C
    L= 6 (????)
    t= L/v(x)

    F=eE,
    F=ma,
    ma=eE
    a=eE/m
    where e = 1.6•10⁻¹⁹ C,
    m=9.1•10⁻³¹ kg,
    v(y)=at =...

    v=sqrt{v(x) ²+v(y) ²} =…

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