Ask questions and get helpful answers.

A golf ball was hit and projected in an angle of 60 degrees with the horizontal. if the initial velocity of the ball was 50m/s, calculate the following:

a. the time the golf ball was in the air
b. horizontal distance the ball traveled
c. maximum height the ball reached

  1. 👍
  2. 👎
  3. 👁
  4. ℹ️
  5. 🚩

4 answers

  1. a) 2 Vo sin60/ g

    b) 2 Vo^2 sin60 cos60/g = Vo^2 sin120/ g

    c) Vo^2*sin^2 60/(2g)

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  2. Can i see the formula?

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  3. 8.83 s
    221 m
    95.66 m

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
  4. May i have your formula please!

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩

Answer this Question

Related Questions

Still need help?

You can ask a new question or browse existing questions.