the perimeter of a pool is 150m. the width is 1/2 its length. what are the dimensions of the pool

P = 2L + 2W

150 = 2L + 2(1/2L)

150 = 3L

? = L

To find the dimensions of the pool, we need to set up an equation using the given information.

Let's assume the length of the pool is "L" meters.

According to the problem, the width of the pool is 1/2 its length, so the width would be (1/2)L = L/2 meters.

The perimeter of a rectangle is given by the formula:
Perimeter = 2(length + width)

Substituting the values we have, the equation becomes:
150 = 2(L + L/2)

Now we can solve this equation to find the value of L (length).

First, simplify the equation:
150 = 2(3L/2)
150 = 3L

Now divide both sides of the equation by 3 to isolate L:
150/3 = L
50 = L

So, the length of the pool is 50 meters.

To find the width, substitute this value back into the equation:
Width = L/2 = 50/2 = 25 meters.

Therefore, the dimensions of the pool are:
Length = 50 meters
Width = 25 meters