On another planet, the isotopes of titanium have the following natural abundances.

Isotope 46Ti Abundance 70.900% Mass(amu) 45.95263

Isotope 48Ti Abundance 10.000% Mass(amu) 47.94795

Isotope 50Ti Abundance 19.100% Mass(amu) 49.94479

What is the average atomic mass of titanium on that planet?

I got 46.9 amu but it is wrong.

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1. (45.95263*0.7090) + (47.94795*0.10) + (49.9479*0.191) = ?

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2. 15.64

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3. i have no idea

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4. You forgot your significant figures.

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5. 46.70 amu

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6. .70900 x 45.95263 = 32.580
.10000 x 49.94479 = 4.7948
.19100 x 49.94479 = 9.5395
*(Be aware that these answers must have 5 significant figures)

32.580 + 4.7948 + 9.5395 = 46.918
*(Be aware that the final answer must go to 3 decimal places)

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7. 46.83
Remember that while calculating you are not suppose to approximate not until you arrive at your final answer.

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8. I'm sorry I posted the right answer to the wrong question

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9. 46.713 you welcomw

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10. It’s 46.811 u

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11. 46.627 u is the correct answer

There are three isotopes of titanium present, 46Ti, 48Ti, and 50Ti, so there are three terms in the weighted average equation.

average atomic mass=(45.95263 u×74.500%100%)+(47.94795 u×17.200%100%)

+(49.94479 u×8.300%100%)

average atomic mass=46.627 u

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