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A ball is thrown vertically upwards from a height of 6 ft with an initial velocity of 60 ft per second. How high will the ball go? Note that the acceleration of the ball is given by a(t)= 32 feet per second per second.

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  1. h(t) = 6+60t-16t^2
    max height at t = -60/-32 = 15/8
    h(15/8) = 62.25 ft

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