This soidum hydroxide solution was then used to determine the amount of acetic acid in vinegar. Three titrations of the sodium hydroxide solution against exactly 5mL of vinegar using phenolphthalein indicator required 22.85Ml, 22.67mL and 22.93mL of the sodium hydroxide solution. What is the molarity of the acetic acid in vinegar?
The molarity of sodium hydroxide solution is .347M
volumebase*molaritybase=volumeacid*molarityacid
I would add the three volumes given,usw 15ml for volume acid, thensolve for Molarityacid
To determine the molarity of acetic acid in vinegar, we can use the concept of neutralization reactions and stoichiometry. The balanced equation for the reaction between acetic acid (CH3COOH) and sodium hydroxide (NaOH) is:
CH3COOH + NaOH → CH3COONa + H2O
From the given information, we know that the sodium hydroxide solution has a molarity of 0.347 M. We can use this information, along with the volume of the sodium hydroxide solution used in the titrations, to calculate the amount of moles of sodium hydroxide used in each titration.
Titrations:
Volume of sodium hydroxide solution used in the first titration = 22.85 mL
Volume of sodium hydroxide solution used in the second titration = 22.67 mL
Volume of sodium hydroxide solution used in the third titration = 22.93 mL
To calculate the moles of sodium hydroxide (NaOH) used in each titration, we can use the formula:
moles = molarity × volume (in liters)
Converting the volumes to liters:
Volume of sodium hydroxide solution used in the first titration = 22.85 mL = 0.02285 L
Volume of sodium hydroxide solution used in the second titration = 22.67 mL = 0.02267 L
Volume of sodium hydroxide solution used in the third titration = 22.93 mL = 0.02293 L
Calculating the moles of sodium hydroxide used in each titration:
Moles of sodium hydroxide used in the first titration = 0.347 M × 0.02285 L
Moles of sodium hydroxide used in the second titration = 0.347 M × 0.02267 L
Moles of sodium hydroxide used in the third titration = 0.347 M × 0.02293 L
Now, since the reaction is 1:1 between acetic acid and sodium hydroxide, the moles of sodium hydroxide used in each titration will be equal to the moles of acetic acid in the vinegar.
Adding the three moles together:
Total moles of acetic acid = Moles from the first titration + Moles from the second titration + Moles from the third titration
Finally, to calculate the molarity of the acetic acid in vinegar, we need to divide the moles of acetic acid by the volume of vinegar used in each titration.
Let's assume that the volume of vinegar used in each titration is 5 mL (as mentioned in the question). Now, we can use the formula:
Molarity (acetic acid) = Moles of acetic acid / Volume of vinegar (in liters)
Substituting the values, we obtained earlier:
Molarity (acetic acid) = Total moles of acetic acid / [Volume of vinegar (5 mL) × 0.001 L/mL]
By following these steps and performing the calculations, you can find the molarity of acetic acid in the vinegar using the given information.