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How many grams of calcium carbonate, CaCO3, do you need in an antacid tablet to neutralize 20 mL of stomach acid? (stomach acid is 0.1 M HCl. There are 3.65g of HCl in 1L of stomach acid or 1g of HCl in 274g of stomach acid).

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3 answers
  1. You have more information in the problem than you need.
    Write the equation.
    CaCO3 + 2HCl ==> CaCl2 + CO2
    mols HCl = M x L = 0.1M x 0.020 L = ?
    mols CaCO3 = 1/2 that (from the coefficients in the balanced equation).
    Then grams CaCO3 = mols CaCO3 x molar mass CaCO3.

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  2. I didn't furnish the exact equation but it doesn't change anything in my answer.
    CaCO3 + 2HCl ==> CaCl2 + CO2 + H2O

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  3. 20ml solution (3.65/1000ml)(1mol hcl/36.4527gHcl)(1mol CaCo3/2molHCl) (100.0872 g CaCo3/1 mol CaCo3)= 0.1002g CaCo3

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