A submarine dives 133.0 m at an angle of 16.0◦ below the horizontal.

A.)What is the horizontal component of the submarine’s displacement? Answer in units of m

B.)What is the vertical component of the submarine’s displacement? Answer in units of m

d = 133m @ (-16o).

A. X = 133*cos(-16) = 128 m.

B. Y = 133*sin(-16) = -36.7 m.

A submarine dives 110.0 m at an angle of 110 degrees below the horizontal. What are the two components?

A.) The horizontal component of the submarine's displacement is a bit of a fishy tale - it remains unchanged, my friend! Since the submarine is diving at an angle below the horizontal, the horizontal displacement remains the same as the submarine's initial position. So the horizontal component of displacement is 0 m.

B.) Ah, the vertical component of the submarine's displacement, now that's a tidal wave of information! To calculate it, we need to use some trigonometry. Based on the given angle of 16.0 degrees, we can find the vertical component using the formula:

Vertical displacement = Diving depth * sin(angle)

Plugging in the values, we get:

Vertical displacement = 133.0 m * sin(16.0°)

I'm calculating, I'm calculating... *drumroll*... Voila! The vertical component of the submarine's displacement is approximately 36.2 m.

To find the horizontal and vertical components of the submarine's displacement, we can use trigonometry.

Given:
Distance d = 133.0 m
Angle θ = 16.0° below the horizontal

A.) Horizontal component of displacement:
The horizontal component is given by the formula: horizontal displacement = distance * cos(angle)

Using the formula:
horizontal displacement = 133.0 m * cos(16.0°)

Calculating:
horizontal displacement ≈ 126.99 m

Therefore, the horizontal component of the submarine's displacement is approximately 126.99 m.

B.) Vertical component of displacement:
The vertical component is given by the formula: vertical displacement = distance * sin(angle)

Using the formula:
vertical displacement = 133.0 m * sin(16.0°)

Calculating:
vertical displacement ≈ 45.36 m

Therefore, the vertical component of the submarine's displacement is approximately 45.36 m.

To find the horizontal and vertical components of the submarine's displacement, we can use trigonometry.

A.) The horizontal component can be found using the cosine of the angle. We can use the equation:

Horizontal component = Displacement * Cos(angle)

In this case, the displacement is the distance the submarine dives, which is given as 133.0 m, and the angle is 16.0 degrees. Plugging these values into the equation, we get:

Horizontal component = 133.0 m * Cos(16.0 degrees)

Calculating this, we get:

Horizontal component = 133.0 m * 0.9603 ≈ 127.6257 m

Therefore, the horizontal component of the submarine's displacement is approximately 127.6257 m.

B.) The vertical component can be found using the sine of the angle. We can use the equation:

Vertical component = Displacement * Sin(angle)

Using the same values as before, we can calculate the vertical component:

Vertical component = 133.0 m * Sin(16.0 degrees)

Calculating this, we get:

Vertical component = 133.0 m * 0.2756 ≈ 36.5868 m

Therefore, the vertical component of the submarine's displacement is approximately 36.5868 m.