A chemical reaction in a bomb calorimeter evolves 3.86 kJ of energy in the form of heat. If the temperature of the bomb calorimeter increases by 4.17 K, what is the heat capacity of the calorimeter?
3860 = Ccal x delta T.
Substitute and solve for Ccal.
311 J/K
First, you change Kj to joules then divide by 4.17K. The answer is 926J/K
To find the heat capacity of the calorimeter, we can use the equation:
Heat capacity (C) = q / ΔT
Where:
- C is the heat capacity of the calorimeter,
- q is the energy evolved in the chemical reaction (in this case, 3.86 kJ), and
- ΔT is the change in temperature of the calorimeter (in this case, 4.17 K).
Now, let's plug in the given values into the equation:
C = 3.86 kJ / 4.17 K
To get the answer, we need to convert the kilojoules (kJ) to joules (J) since the SI unit for heat is in joules:
1 kJ = 1000 J
So, we have:
C = (3.86 kJ * 1000 J/kJ) / 4.17 K
C ≈ 926 J/K
Therefore, the heat capacity of the calorimeter is approximately 926 J/K.