area of a trapizoid:A==h/2(b1=b2). solve for h don't know how so solve it
the equal signb1=b2 should be b1+b2
A = h(b1+b2)/2
2A = h(b1+b2)
h = 2A/(b1+b2)
just do things step by step.
first do addition/subtraction to isolate the h term (none required here)
then do multiplication/division to isolate h.
Note that the manipulations done to solve an equation are done in the reverse order of evaluating an expression. There you do multiplication first, then addition.
Rather than evaluating an expression, you're unwinding it to get at an individual item.
thanks i get it now
To find the formula for the area of a trapezoid, we can substitute the given values into the formula A = h/2(b1 + b2), where A represents the area, b1 represents the length of the first base, b2 represents the length of the second base, and h represents the height of the trapezoid.
In this case, we need to solve the equation for h. Let's rearrange the formula to isolate h.
A = h/2(b1 + b2)
First, multiply both sides of the equation by 2 to get rid of the fraction:
2A = h(b1 + b2)
Next, divide both sides of the equation by (b1 + b2) to isolate h:
h = 2A / (b1 + b2)
Now, you can use this formula to calculate the value of h by plugging in the values of A, b1, and b2.