NaI(aq)+Hg2(C2H3O2)2(aq)-->
Express your answer as a chemical equation. Enter NOREACTION if no reaction occurs. Identify all of the phases in your answer.
I need help! Someone please help..
Here is a simplified set of solubility rules.
http://www.files.chem.vt.edu/RVGS/ACT/notes/solubility_rules.html
Use that to know Hg2I2 is insoluble; therefore, the reaction is
2NaI(aq) + Hg2(C2H3O2)2(aq) ==> 2NaC2H3O2(aq) + Hg2I2(s)
2NaI(aq)+Hg2(C2H3O2)2(aq)→2NaC2H3O2(aq)+Hg2I2(s)
Sure, I'm here to help! Let's analyze the given chemical equation:
NaI(aq) + Hg2(C2H3O2)2(aq)
First, we need to balance the equation:
2NaI(aq) + Hg2(C2H3O2)2(aq) → 2NaC2H3O2(aq) + HgI2(s)
Now, let's identify the phases:
2NaI(aq) + Hg2(C2H3O2)2(aq) → 2NaC2H3O2(aq) + HgI2(s)
NaI(aq) and Hg2(C2H3O2)2(aq) are both aqueous solutions (denoted by "(aq)").
NaC2H3O2(aq) is also an aqueous solution (denoted by "(aq)").
HgI2(s) is a solid (denoted by "(s)").
So, the balanced chemical equation with phases is:
2NaI(aq) + Hg2(C2H3O2)2(aq) → 2NaC2H3O2(aq) + HgI2(s)
I hope this helps!
To determine the products of a reaction, we need to look at the reactants involved and their corresponding chemical formulas.
In this case, we have NaI (sodium iodide) and Hg2(C2H3O2)2 (mercury(II) acetate). To predict the products, we need to look at the solubility rules for both substances.
According to the solubility rules, all sodium salts (including NaI) are soluble in water. Similarly, mercury(II) acetate (Hg2(C2H3O2)2) is also soluble in water.
When two soluble ionic compounds react in an aqueous solution, they often undergo a double displacement reaction, also known as a precipitation reaction. In this type of reaction, the cations and anions in the reactants exchange partners to form new compounds.
Using the formula of the reactants, we can determine the possible products of the reaction:
NaI(aq) + Hg2(C2H3O2)2(aq)
Since both NaI and Hg2(C2H3O2)2 are soluble in water, they will dissociate into their respective ions:
Na+(aq) + I-(aq) + Hg2 2+(aq) + 2(C2H3O2)-(aq)
Now, to predict the products, we need to examine the possible combinations of the ions:
1. Na+(aq) combines with 2(C2H3O2)-(aq) to form sodium acetate (NaC2H3O2):
Na+(aq) + 2(C2H3O2)-(aq) → NaC2H3O2(aq)
2. I-(aq) reacts with Hg2 2+(aq) to form a precipitate of mercury(II) iodide (HgI2):
I-(aq) + Hg2 2+(aq) → HgI2(s)
Thus, the complete balanced chemical equation, including the phases, is:
NaI(aq) + Hg2(C2H3O2)2(aq) → NaC2H3O2(aq) + HgI2(s)
Note: It is important to always balance the equation by adjusting the coefficients to ensure the conservation of matter.