Two large containers each contain the same amount of juice. When 54oz. of the first container are poured into the second container, the second container has 4 times as much juice as the first container. How many ounces of juice did the first container originally have?
at start:
container A has x oz
container B has x oz
after pouring:
container A has x-54
container B has x+54
x+54 = 4(x-54)
x+54 = 4x - 216
-3x = -270
x = 90
check:
90-54 = 36
90+54 = 144
IS 144 equal to 4 times 36 ? YEAh
i dont get it
Let's assume the amount of juice in each container is "x" ounces.
When 54oz. of juice from the first container are poured into the second container, the second container has 4 times as much juice as the first container. This can be represented as:
x + 54 = 4x
Now, let's solve for x:
Subtracting x from both sides:
54 = 3x
Dividing both sides by 3:
x = 18
Therefore, the first container originally had 18 ounces of juice.
To solve this problem, let's use algebra. Let's assume that the original amount of juice in each container is denoted by x ounces.
When 54 ounces of juice from the first container are poured into the second container, the second container now has 4 times as much juice as the first container. This can be written as:
x + 54 = 4x
To solve for x, we need to isolate it on one side of the equation.
Subtracting x from both sides:
54 = 4x - x
Combining like terms:
54 = 3x
To isolate x, divide both sides of the equation by 3:
54/3 = x
x = 18
Therefore, the first container originally had 18 ounces of juice.