If the standard enthalpy of combustion of octane, C8H18(l) is -5471 kJ/mol, calculate the enthalpy change when 1.00 kg of octane are burned. the molar mass of octane is 114 g/mol

First we will find out the amount of grams of octane burned.

1 kg octane * 1000 g / 1 kg = 1000 g octane.

Now we will find the moles of octane burned:

1000 g octane / 114 g/mol octane = 8.772 mol octane burned.

Now that we have the amount of moles, we can find out how much enthalpy changed by multiplying the moles of octane burned times that amount of heat lost per mole.

-5471 kJ/mol * 8.772 mol = -48000 kJ

You're welcome

Oh, burning octane, huh? Time to light things up! Alright, let's calculate the enthalpy change.

First, we need to convert the mass of octane from kilograms to grams. Since there are 1,000 grams in 1 kilogram, we have 1.00 kg x 1,000 g/kg = 1,000 grams of octane.

Next, we can determine the number of moles of octane. Given that the molar mass of octane is 114 g/mol, we divide the mass (1,000 g) by the molar mass: 1,000 g / 114 g/mol = 8.77 mol.

Now, it's time to calculate the enthalpy change using the stoichiometry of the combustion reaction. The given enthalpy change is -5471 kJ/mol. Since we have 8.77 moles of octane, we can multiply the enthalpy change by the number of moles: -5471 kJ/mol x 8.77 mol = -47,979.67 kJ.

So, the enthalpy change when 1.00 kg of octane is burned is approximately -47,979.67 kJ. That's quite a fiery reaction!

To calculate the enthalpy change when 1.00 kg of octane is burned, we need to convert the mass of octane from kilograms to moles.

Step 1: Convert mass from kilograms to grams
1.00 kg = 1000 grams

Step 2: Calculate moles of octane
molar mass of octane = 114 g/mol
moles of octane = mass of octane / molar mass of octane
moles of octane = 1000 grams / 114 g/mol

Step 3: Calculate the enthalpy change
enthalpy change = moles of octane x enthalpy of combustion
enthalpy change = (1000 grams / 114 g/mol) x (-5471 kJ/mol)

Calculating this equation will give the enthalpy change in kilojoules (kJ) when 1.00 kg of octane is burned.

To calculate the enthalpy change when 1.00 kg of octane is burned, we need to convert the mass of octane from kilograms to moles.

Step 1: Convert the mass of octane from kilograms to grams:
1.00 kg = 1000 g (since there are 1000 grams in 1 kilogram).

Step 2: Convert the mass of octane from grams to moles using the molar mass:
Molar mass of octane (C8H18) = 114 g/mol.
Number of moles = (mass of octane in grams) / (molar mass of octane).
Number of moles = 1000 g / 114 g/mol = 8.77 mol (rounded to two decimal places).

Step 3: Calculate the enthalpy change using the given standard enthalpy of combustion:
Enthalpy change = (number of moles) × (standard enthalpy of combustion).
Enthalpy change = 8.77 mol × (-5471 kJ/mol) = -47909.67 kJ.

Therefore, the enthalpy change when 1.00 kg of octane is burned is approximately -47909.67 kJ.