Write a net ionic equation for the reaction that occurs when aqueous solutions of potassium hydroxide and nitrous acid are combined.
HNO2 (aq) + OH- (aq) ==> NO2- (aq) + H2O (l)
Sure, here's a net ionic equation for you:
2 OH- (aq) + HNO2 (aq) -> 2 H2O (l) + NO2- (aq)
To write the net ionic equation for the reaction between potassium hydroxide (KOH) and nitrous acid (HNO2), we need to first write the balanced molecular equation.
Step 1: Write the balanced molecular equation by combining the two reactants and predicting the products of the reaction:
KOH(aq) + HNO2(aq) → KNO2(aq) + H2O(l)
In this reaction, potassium hydroxide (KOH) reacts with nitrous acid (HNO2) to form potassium nitrite (KNO2) and water (H2O).
Step 2: Next, write the complete ionic equation by breaking down all the aqueous substances into their individual ions:
K+(aq) + OH-(aq) + H+(aq) + NO2-(aq) → K+(aq) + NO2-(aq) + H2O(l)
In the complete ionic equation, potassium hydroxide and nitrous acid are dissociated into their respective ions.
Step 3: Finally, write the net ionic equation by removing the spectator ions, which are the ions that appear on both sides of the equation and do not participate in the reaction:
OH-(aq) + H+(aq) → H2O(l)
In the net ionic equation, the potassium ion (K+) and nitrite ion (NO2-) are spectator ions and are not involved in the chemical reaction. Thus, we are left with the net ionic equation as shown above, which represents the actual reaction taking place.
KOH + HNO2 ==> KNO2 + H2O
net ionic is
OH^- + H^+ ==>H2O