What is the pH of the resulting solution if 30.00 mL of 0.100M acetic acid is added to 10.00mL of 0.100 M NaOH? For acetic acid, Ka=0.000018.
I know that NaOH is a strong base and acetic acid is a weak acid. What is the equation: C6H5COOH+NaOH<--> C6H5COOH
Once I get this, I think I'll be able to use Ka from there. Thanks.
The equation is
CH3COOH + NaOH ==> CH3COONa + H2O
(What you wrote--C6H5COOH-- is benzoic acid).
I would convert M and L to mols and use the Henderson-Hasselbalch equation. Post your work if you get stuck.