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What is the pH of the resulting solution if 30.00 mL of 0.100M acetic acid is added to 10.00mL of 0.100 M NaOH? For acetic acid, Ka=0.000018.

I know that NaOH is a strong base and acetic acid is a weak acid. What is the equation: C6H5COOH+NaOH<--> C6H5COOH
Once I get this, I think I'll be able to use Ka from there. Thanks.

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  1. The equation is
    CH3COOH + NaOH ==> CH3COONa + H2O
    (What you wrote--C6H5COOH-- is benzoic acid).
    I would convert M and L to mols and use the Henderson-Hasselbalch equation. Post your work if you get stuck.

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