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A particle has an acceleration of +6.24 m/s2 for 0.300 s. At the end of this time the particle's velocity is +9.81 m/s. What was the particle's initial velocity?

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4 answers

  1. v=v₀ +at
    v₀ = v-at

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  2. v=vo +at
    vo=v v-at
    vo=9.81m/s - (6.24m/s^2(.3s))
    vo=9.81m/s - 1.872m/s
    vo= 7.44m/s

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  3. 7.44

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  4. What is your question about this problem? I will be happy to critique your thinking. We are not in the habit of doing homework or tests for students.

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