Sulfuric acid, H2SO4, is sold as a 36% aqueous solution.

What is this concentration in
A. Molality
B. Molarity
C. The Mole Fraction

Please and thank you. :)

You must have the density to answer the question. I have my handy dandy qual book I used about 60 years ago and it lists 36% H+2SO4 as having density of about 1.27 g/mL. You can't find tables like that in qual? books these days mostly because there aren't any qual books anymore. In fact most schools have done away with qual and replaced it with a second half of freshman chemistry but that's a band aid. Enough of my soap box and to the question.

1.27 g/mL x 1000 mL x 0.36 x (1/molar mass H2SO4) = mols/L = M = part b.

(Note: 1.27 g/mL x 1000 is the mass of 1 L of the solution, that times 0.36 is the mass of H2SO4 in that solution and that times 1/molar mass H2SO4 gives mols H2SO4/L which is M.)

part a.
You have moles from above. Divide by kg solvent. Find solvent by mass soln - mass H2SO4.

part c.
mols H2SO4 you have.
mols H2O = grams H2O/molar mass H2O
XH2SO4 = nH2SO4/total mols.

To determine the concentration of sulfuric acid (H2SO4) in molality, molarity, and mole fraction, we need to know the definition of each term and the necessary information.

A. Molality:
Molality (m) is the concentration expressed in moles of solute per kilogram of solvent. To calculate molality, we use the formula:

Molality (m) = moles of solute / mass of solvent (in kg)

In this case, we know that the sulfuric acid solution is 36% aqueous, which means it contains 36 grams of sulfuric acid in 100 grams of solution. To find the molality, we need to convert these values to moles:

Mass of sulfuric acid = (36% * 100 g) = 36 g
Molar mass of H2SO4 = 2(1.008) + 32.06 + 4(16) = 98.09 g/mol

Moles of H2SO4 = mass / molar mass = 36 g / 98.09 g/mol

Now we need to find the mass of water (solvent) in the solution. Since the solution is 36% aqueous, the remaining 64 grams of the solution is water.

Mass of water = 64 g = 0.064 kg

Finally, we can calculate the molality using the formula:

Molality (m) = moles of H2SO4 / mass of water (in kg)

B. Molarity:
Molarity (M) is the concentration expressed in moles of solute per liter of solution. To calculate molarity, we use the formula:

Molarity (M) = moles of solute / volume of solution (in liters)

In this case, we need to determine the number of moles of sulfuric acid in the solution. We can use the same value calculated earlier:

Moles of H2SO4 = 36 g / 98.09 g/mol

To calculate the volume of the solution, we need to assume a total volume. Let's assume we have 1 liter of solution.

Molarity (M) = moles of H2SO4 / volume of solution (in liters)

C. Mole Fraction:
The mole fraction (X) is the ratio of the moles of one component to the total moles of all components in the solution. To calculate the mole fraction, we use the formula:

Mole fraction (X) = moles of solute / total moles of all components

For the mole fraction calculation, we need the moles of sulfuric acid (H2SO4) and moles of water (H2O), which we have already calculated earlier.

Mole fraction of H2SO4 = moles of H2SO4 / (moles of H2SO4 + moles of H2O)

Now that we have explained the necessary steps and formulas, let's compute the answers:

A. Molality: Calculate the moles of H2SO4 and then divide by the mass of water in kilograms.
B. Molarity: Calculate the moles of H2SO4 and divide by the assumed volume of the solution in liters.
C. Mole Fraction: Calculate the moles of H2SO4 and moles of H2O, then use the mole fraction formula to find the ratio.

Please let me know if you need further assistance with the calculations.