what average force is needed to accelerate a 7.00-gram pellet from rest to 125m/s over distance of a .800m along the barrel of a rifle.

a = (V^2-Vo^2)/2d.

a = (15625-0)/1.60 = 9766 m/s^2.

F = ma = 0.007 * 9766 = 68.4 N.

what steps did you take to get the numbers for (a)

V^2= U^2 + 2as

125^2 = 2a(0.8)
15625 = 1.6a
a = 9765.62 m/s^2

F = ma
= (0.007)(9765.62)
= 68.4 N

WHAT THE HELLA RE YOU GUYS DOING

nevermind you have to take g to kg in order to get N right

yeah mads

why are u getting 0.007