What volume would a 0.0871 gram sample of air occupy if the density of air is 1.29 g/L
mass = volume x density
Substitute and solve for volume.
To find the volume occupied by a 0.0871 gram sample of air, we can use the formula:
Volume = Mass / Density
First, let's convert the density of air to grams per cubic centimeter (g/cm³).
We know that 1 L = 1000 cm³, so to convert density from g/L to g/cm³, we divide the density by 1000:
Density in g/cm³ = Density in g/L / 1000
Density in g/cm³ = 1.29 g/L / 1000 = 0.00129 g/cm³
Now, we can calculate the volume:
Volume = Mass / Density
Volume = 0.0871 g / 0.00129 g/cm³
Volume ≈ 67.44 cm³
Therefore, a 0.0871 gram sample of air would occupy approximately 67.44 cubic centimeters of volume.
To calculate the volume occupied by the given sample of air, we can use the formula:
Volume = Mass / Density
First, we need to make sure that the units for mass and density are consistent. The given mass of the air sample is 0.0871 grams. The density of air is given as 1.29 g/L (grams per liter).
Now, we can substitute the values into the formula:
Volume = 0.0871 g / 1.29 g/L
To divide the two values, we can convert the density to grams per gram by converting liters to milliliters (since 1 milliliter is equal to 1 gram):
Volume = 0.0871 g / (1.29 g/1000 mL)
Simplifying the expression:
Volume = 0.0871 g / (1.29 g/1000 mL)
= 0.0871 g * (1000 mL/1.29 g)
= 67.829 mL
Therefore, a 0.0871 gram sample of air would occupy a volume of 67.829 milliliters.