The length of a rectangle is 9.7cm more than 4 times the width. If the perimeter of the rectangle is 9.1cm what are its dimensions?
Could someone please explain, not looking for just answer, needing to know how to do it.
if anyone’s taking algebra 2 on connexus pls add me on insta @lvr.sarah im tryna find someone to work w in that class lmfao
Steve you were right missed wrote.the length is 9.7cm more than 4 times the width and the perimeter is 91.4cm.
Well, let's solve this problem with a little bit of humor, shall we?
So, we have a rectangle with a certain width and length, let's say width = W and length = L. According to the problem, the length is 9.7cm more than 4 times the width.
So, L = 4W + 9.7. Easy-peasy, right? Now, let's move on to the perimeter of the rectangle.
The perimeter of a rectangle is given by the formula: P = 2L + 2W. And in this case, we are given that the perimeter is 9.1cm.
Now, let's substitute L with 4W + 9.7 in the perimeter formula: 9.1 = 2(4W + 9.7) + 2W.
Time for some math magic! Let's simplify this equation: 9.1 = 8W + 19.4 + 2W.
Hmm, let's combine the similar terms: 9.1 = 10W + 19.4.
Now, let's isolate W by subtracting 19.4 from both sides: 9.1 - 19.4 = 10W.
Oh no! It seems that we have a negative number here... I told you math could be brutal sometimes! But don't worry, let's keep going.
Simplifying further: -10.3 = 10W.
Divide both sides by 10: -1.03 = W.
Well, apparently W has a strange value of -1.03... This is getting weirder by the second! But don't panic. Math is like a rollercoaster ride, and sometimes we encounter unexpected twists and turns.
Now, let's substitute this strange W value back into our equation for L: L = 4(-1.03) + 9.7.
Calculating that, we get L ≈ 5.88.
So it seems like we have a rectangle with a negative width, and a length of approximately 5.88cm. But hold on a second! A negative width? That doesn't make any sense, does it?
I'm sorry to say this, but it seems we might have a bit of a mathematical clown act going on here. This rectangle doesn't exist in the real world.
Well, let's hope we find a friendlier and more sensible problem to solve next time. Keep smiling and remember, math can be both challenging and amusing!
To solve this problem, we need to use the given information about the relationship between the length and width of the rectangle. Let's break down the problem into steps:
Step 1: Assign variables
Let's assume that the width of the rectangle is 'W' cm. We can then express the length of the rectangle as '4W + 9.7' cm, as given in the problem.
Step 2: Define the perimeter
The perimeter of a rectangle is the sum of all its sides. In this case, the length of the rectangle is equal to two sides, and the width of the rectangle is equal to the remaining two sides. Therefore, the perimeter can be calculated as:
Perimeter = Length + Length + Width + Width
Or, in equation form:
9.1 = (4W + 9.7) + (4W + 9.7) + W + W
Step 3: Simplify the equation
Let's simplify the equation by combining like terms:
9.1 = 8W + 19.4 + 2W
Step 4: Solve for W
By combining like terms and bringing all terms to one side of the equation, we get:
0 = 10W + 28.4 - 9.1
10W = -19.3
Step 5: Solve for W
Dividing both sides of the equation by 10, we find that:
W = -1.93
Step 6: Check the result
Since the width of a rectangle cannot be negative, we need to re-evaluate the problem or check for any errors in the problem statement or calculations.
Please note that in the provided problem, the solution comes out to be a negative width, which is not possible for a rectangle. Double-check the information you have given or re-evaluate the problem to ensure all values are correct.
width = w
length = 4w+9.7
p = 2(w + 4w+9.7) = 9.1
w = -1.03
That seems odd, since widths are usually positive. But, looking at the data given, it's impossible for the length to be greater than 9.7 and have the perimeter be only 9.1
Better fix it if you want a sensible answer.