a bullet is fired horizontally with an initial velocity of 600 m/s at a target located 300 m from the rifle. how much time is required for the bullet to reach the target? (B) using the approximate value of g=10 m/s squared how far does the bullet fall in this time?

time=distance/speed

b) distance fell=1/2 g t^2

To determine the time required for the bullet to reach the target, you can use the formula:

time = distance / velocity

In this case, since the bullet is fired horizontally, the initial vertical velocity is 0 m/s. So the initial velocity is the horizontal velocity of 600 m/s. The distance is given as 300 m.

Substituting these values into the formula:

time = 300 m / 600 m/s
time = 0.5 s

Therefore, it takes 0.5 seconds for the bullet to reach the target.

To determine how far the bullet falls in this time, you can use the formula:

distance = 0.5 * g * time^2

Given that the approximate value of g is 10 m/s^2, and the time is 0.5 s, you can calculate:

distance = 0.5 * 10 m/s^2 * (0.5 s)^2
distance = 0.5 * 10 m/s^2 * 0.25 s^2
distance = 1.25 m

Therefore, the bullet falls approximately 1.25 meters in this time.

To find the time required for the bullet to reach the target, we can use the equation of motion for horizontal projectile motion:

Distance = Speed × Time

In this case, the distance is 300 m, and the speed is 600 m/s. We want to find the time, so we rearrange the equation:

Time = Distance / Speed

Plugging in the given values:

Time = 300 m / 600 m/s

Time = 0.5 s

So, it would take the bullet 0.5 seconds to travel the 300 m distance.

Now, let's calculate how far the bullet falls during this time. Since the bullet is fired horizontally, it only experiences motion in the vertical direction due to the force of gravity. We can use the equation of motion for vertical motion:

Distance = (1/2) × Acceleration × Time^2

In this case, the acceleration due to gravity is given as g = 10 m/s^2, and the time is 0.5 s. Plugging these values into the equation:

Distance = (1/2) × 10 m/s^2 × (0.5 s)^2

Distance = (1/2) × 10 m/s^2 × 0.25 s^2

Distance = 1.25 m

Therefore, the bullet falls approximately 1.25 meters during the 0.5 seconds it takes to reach the target.