write a function whose graph is the graph of y=x^2, but is shifted to the left 6 units.

f(x-h) is f(x) shifted right h units. So, you want

y = (x+6)^2

Sure, here's a function that will shift the graph of y = x^2 to the left by 6 units:

```python
def shifted_graph(x):
shifted_x = x + 6 # Shifting x-axis to the left by 6 units
y = shifted_x**2 # Computing the y-value
return y
```

Now when we plug in an x-value into this function, it will give us the corresponding y-value on the shifted graph.

To shift the graph of the function y = x^2 to the left 6 units, we need to replace x with (x + 6) in the equation.

Therefore, the function you are looking for is:

f(x) = (x + 6)^2

To shift a graph to the left by a certain value, we need to subtract that value from the x-coordinate of each point on the original graph. In this case, we want to shift the graph of y=x^2 to the left by 6 units.

To write a function that represents this shifted graph, we can start with the basic function y=x^2 and apply the necessary transformation.

Let's call the shifted function f(x). To shift it to the left by 6 units, we need to subtract 6 from the x-coordinate:

f(x) = (x - 6)^2

This means that for any given x-value, we subtract 6 from it before squaring it. This will produce a new function whose graph is the graph of y=x^2, but shifted 6 units to the left.

Why don't you read your textbook and figure it out? There are examples. but anyways:

y=x^2 is a parabola, so after you draw a standard parabola, just count 6 units left for each points.