Calculate the volume of water, in milliliters, that would be displaced by a piece of gold weighing 18.2g.

To calculate the volume of water displaced by a piece of gold, we need to use the concept of density. The density of gold is 19.3 grams per milliliter (g/mL).

The formula for calculating volume (V) is given by:

V = mass / density

In this case, the mass of the gold is 18.2g.

Let's plug in the values into the formula:

V = 18.2g / 19.3 g/mL

V ≈ 0.943 mL

Therefore, the volume of water displaced by a piece of gold weighing 18.2g is approximately 0.943 milliliters.

To calculate the volume of water displaced by a piece of gold weighing 18.2g, we need to use the principle of buoyancy. The volume of water displaced by the gold will be equal to the volume of the gold object.

Here are the steps to calculate the volume of water displaced:

1. Determine the density of gold:
The density of gold is 19.32 grams per cubic centimeter (g/cm³). This means that 1 cubic centimeter of gold weighs 19.32 grams.

2. Convert the weight of gold from grams to kilograms:
Divide the weight of gold, 18.2 grams, by 1000 to convert it to kilograms.
18.2 g ÷ 1000 = 0.0182 kg

3. Calculate the volume of gold using the density formula:
Density = Mass / Volume
Rearrange the formula to solve for volume:
Volume = Mass / Density
Volume = 0.0182 kg / 19.32 g/cm³
Since the density is in grams, we need to convert the mass from kilograms to grams by multiplying by 1000:
Volume = 0.0182 kg / (19.32 g/cm³ * 1000 g/kg)

4. Convert the volume from cubic centimeters to milliliters:
Since 1 cubic centimeter is equal to 1 milliliter, the volume will be in milliliters:
Volume = 0.0182 kg / (19.32 g/cm³ * 1000 g/kg) = 0.00094 mL

Therefore, the volume of water displaced by a piece of gold weighing 18.2g is approximately 0.00094 milliliters.

volume Au = mass/density = ? cc = ?mL

That many mL will be displaced.