You are trying to compare the Farenheit and Celcius scales and you have two examples; Temperatur A is 50 degrees Celcius and 122 Farenheit. Temperature B is 100 degrees Celcius and 212 degrees Farenheit. What graph models the relationship between Farengeit and Celcius scales? What is an equation of the line in slope intercept form.

I know you cant see the graphs but maybe be able to explain a little.

Not understanding how to graph my answer

I suggest the following:

draw a horizontal axis, called C , for Celsius
draw a vertical axis , called F for Fahrenheit, (note the correct spelling)

label one point as A(50, 122) and another B((100,212)
join with a straight line.
pick any point P(C,F)

slope of PA = slope BA
(F-122)/(C-50) = (212-122)/(100-50)
(F-122)/(C-50) = 90/50 = 9/5
cross-multiply
5F - 610 = 9C - 450
5F = 9C + 160

F = (9/5)C + 32 or re-arrange to get C = ....

your right

To compare the Fahrenheit and Celsius scales, you can create a linear equation that models the relationship between the two scales. The equation will help you convert temperatures from one scale to another.

To find the equation of the line in slope-intercept form, you need two points on the line. Let's use the given examples:

Temperature A: 50 degrees Celsius and 122 degrees Fahrenheit
Temperature B: 100 degrees Celsius and 212 degrees Fahrenheit

To convert these points into slope-intercept form (y = mx + b), we need to find the slope (m) and the y-intercept (b).

First, calculate the slope:
m = (change in y)/(change in x) = (difference in Fahrenheit)/(difference in Celsius)

m = (122 - 212)/(50 - 100) = -90/-50 = 9/5

Since Fahrenheit is the dependent variable (y) and Celsius is the independent variable (x), m represents the change in Fahrenheit divided by the change in Celsius. Therefore, m = 9/5.

Now, we can substitute one of the given points (e.g., 50 degrees Celsius and 122 degrees Fahrenheit) into the slope-intercept form equation: y = mx + b.

122 = (9/5)(50) + b
122 = 90/5 + b
122 = 18 + b

Next, isolate b:
122 - 18 = b
104 = b

Therefore, the equation of the line in slope-intercept form is:
y = (9/5)x + 104

This equation models the relationship between Fahrenheit and Celsius scales. If you have any Celsius temperature (x), you can plug it into the equation and solve for the corresponding Fahrenheit temperature (y).

I believe it would be y=9/5+32 if I made the graph right. Am I close?