An automobile gasoline tank holds 20.0 gal when full. How many pounds of gasoline will it hold if the gasoline has a density of 0.560 g/mL?

What is the mileage in miles per gallon? (Given: 1 km {\rm km} = 0.621 mi {\rm mi} and 1 L {\rm L} = 0.264 gal {\rm gal})

To find the number of pounds of gasoline the automobile gasoline tank will hold, we need to follow these steps:

Step 1: Calculate the volume of gasoline in the tank.
Given that the tank holds 20.0 gallons of gasoline, we can convert this to liters since density is often given in grams per milliliter. There are 3.78541 liters in one gallon. So, the number of liters of gasoline in the tank is:

20.0 gallons * 3.78541 liters/gallon = 75.7082 liters

Step 2: Convert liters to milliliters.
We know that 1 liter is equal to 1000 milliliters. So, to convert liters to milliliters, we multiply by 1000:

75.7082 liters * 1000 mL/liter = 75708.2 mL

Step 3: Calculate the mass of gasoline.
The density of gasoline is given as 0.560 g/mL. Density is defined as mass per unit volume. Therefore, to find the mass of gasoline, we multiply the density by the volume:

75708.2 mL * 0.560 g/mL = 42359.152 g

Step 4: Convert grams to pounds.
To convert grams to pounds, we divide by the conversion factor of 453.59237 grams per pound:

42359.152 g / 453.59237 g/lb = 93.4139 lb

Therefore, the automobile gasoline tank will hold approximately 93.4 pounds of gasoline if the gasoline has a density of 0.560 g/mL.

Assume a gasoline is isooctane, which has a density of 0.692 g/mL. What is the mass of 1.7 gal of the gasoline (1 gal = 3.78 L)?

I would change g/mL to lbs/gallon. Then pounds gasoline = gallons x density in lgs/gallon = ?

The easiest way to change g/mL to lbs/gallon is to use google.