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an aluminum cylinder is 10.0 cm in length and has a radius of .25 cm. if the mass of a single atom of aluminum is 4.48X10^-23 calculate the number of aluminum atoms present in the cylinder. the density of aluminum is 2.70 g/cm^3

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2 answers
  1. g/cm^3 * cm^3 * atoms/g = atoms
    or,
    g/cm^3 * cm^3 ÷ g/atom = atoms

    2.70 * (pi * .25^2 * 10) / (4.48*10^-23) = 1.18 * 10^23

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  2. An aluminum cylinder is 10.0 cm in length and has a radius of 0.25 cm.
    If the mass of a single Al atom is 4.48 × 10−23g, calculate the number of
    Al atoms present in the cylinder. The density of aluminum is 2.70 g/cm

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    2. 👎
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