Write the first six terms of each of the sequences whose nth term is
a)(-3)n { ____, ____, ____, ____ , ____, ____ }
b)3 – 4n { ____, ____, ____, ____ , ____, ____ }
plug in 1 for n for the first term. plug in 2 for second term and so aon until the sixth term
ex:(-3)n
(-3)1=-3
(-3)2= -6
etc... :P
thanks
a) (-3)n { -3, 3, -9, 27, -81, 243 }
b) 3 - 4n { -1, -5, -9, -13, -17, -21 }
To find the first six terms of the sequences, we need to substitute values of n into each expression and evaluate. Let's calculate the terms for each sequence:
a) The nth term is (-3)n.
To find the first six terms, substitute n = 1, 2, 3, 4, 5, and 6 into the expression.
For n = 1: (-3)1 = -3
For n = 2: (-3)2 = 9
For n = 3: (-3)3 = -27
For n = 4: (-3)4 = 81
For n = 5: (-3)5 = -243
For n = 6: (-3)6 = 729
Therefore, the first six terms of the sequence are: -3, 9, -27, 81, -243, 729.
b) The nth term is 3 – 4n.
To find the first six terms, substitute n = 1, 2, 3, 4, 5, and 6 into the expression.
For n = 1: 3 – 4(1) = 3 – 4 = -1
For n = 2: 3 – 4(2) = 3 – 8 = -5
For n = 3: 3 – 4(3) = 3 – 12 = -9
For n = 4: 3 – 4(4) = 3 – 16 = -13
For n = 5: 3 – 4(5) = 3 – 20 = -17
For n = 6: 3 – 4(6) = 3 – 24 = -21
Therefore, the first six terms of the sequence are: -1, -5, -9, -13, -17, -21.