A bullet of mass 10g travelling horizontally at a speed of 100m/s embeds itself in a block of wood of mass 990g suspended by strings so that it can swing freely find:
a.the vertical height through which the block rises.
B.how much of the bullet energy becomes internal energy (g
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1 answer

The law of conservation of linear momentum
mv=(m+M)u
The law of conservation of energy
u =mv/(m+M) = 0.01•100/(0.99+0.01)= 1 m/s.
(m+M)u²/2 =(m+M)gh
h= u²/2•g=1/2•9.8=0.05 m
mv²/2 (m+M)u²/2 = 0.01•10000/2  1•1/2 = 500.5=49.5 J 👍
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